Let’s look at finding the inverse of y=log(x) algebraically. First, recall that y=log(x) is shorthand for y=log₁₀(x).

Step 1: Swap x and y. Now we have x=log₁₀(y).

Step 2: Transform the log equation into exponential form. 10^x=y

Step 3: Replace y with the inverse notation of f^-1(x). Thus, f^-1(x)=10^x

Try a more challenging one on your own, such as f(x)=log₂(x+3)